Using the stoichiometry of the reaction, the mass of mercury produced is 51.5 g.
The equation of the reaction is shown properly as;
2HgO(s) ------> 2Hg(s) + O2(g)
Number of moles of HgO = mass/molar mass
Molar mass of HgO = 216.591 g
Number of moles of HgO = 27.7 g/216.591 g/mol = 0.128 moles
From the reaction equation;
2 mols of HgO yields 1 mole of Hg
0.128 moles of HgO yields 2 mols × 0.128 moles /1 mol = 0.256 moles
Hence mass of mercury = 0.256 moles × 201 g/mol = 51.5 g
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