Question

Find the equation of a line perpendicular to y=-4x that contains the point (-3, -4)

Answer 1

Answer:

y = -4x-16

Step-by-step explanation:

m= - 4

The y-intercept of the line that passes through the given point  (-3,-4) is

-4 = -4(-3) + b

-4= 12 +b

b= -16

The equation of the line that passes through the given point  (-3,-4) is

y =mx +b

y = -4x- 16