The molar concentration of a sucrose solution prepared by dissolving 350.25 g of sucrose is enough deionized water to yield a final solution volume of 500.00 mL is 2.048 M.
We must first obtain the number of moles of sucrose in the solution as follows;
Number of moles = mass/ molar
Mass of sucrose = 350.25 g
Molar mass of sucrose = 342 g/mol
Number of moles of sucrose= 350.25 g / 342 g/mol
= 1.024 moles
Recall that;
Number of moles = concentration × volume
concentration = Number of moles/volume
volume of solution = 500.00 mL or 0.5 L
concentration = 1.024 moles/0.5 L
concentration = 2.048 M
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