Question

I really need help with this ... I've been stuck for ages even though I thought I was doing it right. Can someone please go through and explain to me
(there's a link)...​

Answer 1

Answer:

Step-by-step explanation:

What you are looking for is the height of the water after the sphere enterred

first you find the volume of the water in the container

height of water in cylinder (h) =3/4 x 30cm =22.5 cm

diameter (d)  = 12cm            radius = d/2 =12cm /2 =6cm

Volume (V1)=$\pi$r^2h= 22/7 x (6cm)^2 x 22.5cm =22/7 x 36cm^2 x 22.5cm

                                                                      =2545 cm^3

Then you find the volume of the sphere

Diameter = d = 8cm                           radius = r = 8cm/2 =4cm

π =22/7

Volume (V2 )=(4/3) πr^3 = (4/3) π(4cm)^3 = (4/3) x 22/7 x64cm^3 =268cm^3

total volume after the sphere entered =V1 +V2 =(2545 +268)cm^3

                                                                             =2813cm^3

now yoy use the volume formula but make height the subject

V=πr^2h                     h=V/πr^2h =2813cm^3 /(22/7) x (6cm)^2

                                                    =2813cm^3 x 7 /22 x36cm^2

                                                    =19691cm^3  /  792cm^2

                                                    =24.9 cm

therefore the height of the water in the container is 24.9 cm