Question

According to a survey of 1000 families of any town in 2010AD,794 families have radio and 187 families have television .If 63 families do not have any one of them, then how many families will have both radio and television ? find it
Answer44

Answer 1

• E=1000
• A=794
• B=187
• (A$\cap$B)'=63

AUB=1000-63=937

$\\ \sf\longmapsto A\cap B=A+B-AUB$

$\\ \sf\longmapsto A\cap B=794+187-937[/tex[

[tex]\\ \sf\longmapsto A\cap B=981-937$

$\\ \sf\longmapsto A\cap B=44$