Question

The foot of a 60 kg sprinter is on the ground for 0.20 s while her body accelerates from rest to 2.0 m/s.
What is the magnitude of the friction force?

Answer 1

The magnitude of the friction force is 600 Newton.

Given the following data:

• Mass of sprinter = 60 kg

• Initial velocity, U = 0 m/s (since the sprinter is starting from rest).

• Final velocity, V = 0 m/s

• Time, t = 0.20 seconds.

To find the magnitude of the friction force:

First of all, we would determine the acceleration of the sprinter by using the following formula;

$a = \frac{V \; - \;U}{t}$

Where:

• a is the acceleration.

• V is the final velocity.

• U is the initial velocity.

• t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

$a = \frac{2 \;- \;0}{0.20} \\\\a = \frac{2}{0.20}$

Acceleration, a = 10 $m/s^2$

Now, we would determine the magnitude of the friction force by using Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

$Force = mass$ × $acceleration$

$Force = 60$ × $10$

Force = 600 Newton

Therefore, the magnitude of the friction force is 600 Newton.

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