Respuesta :
hello! your answer would be infinite solutions, or b! hope this helped! ;)
Answer:
Step-by-step explanation
3(k+9)=8-(-3k-19)
=> 3k+27=8+3k+19
=>3k+27-8-3k-19=0
=>0=0
so with all value of k, 3(k+9)=8-(-3k-19) always