Question

A baseball player has a batting average of 0.235. What is the probability that he has exactly 2 hits in his next 7
at bats?

Answer 1

Probabilities are used to determine the chances of an event.

The probability that he hits exactly 2 in the next 7 bats is 0.3039

The given parameters are:

$\mathbf{p = 0.235}$ --- probability that he hits a bat

The question is an illustration of binomial probability, and it is represented as:

$\mathbf{Pr = ^nC_xp^x(1 - p)^{n -x}}$

In this case:

$\mathbf{n = 7}$ --- number of bats

$\mathbf{x = 2}$ --- number of hits

So, we have:

$\mathbf{Pr = ^nC_xp^xq^{n -x}}$

$\mathbf{Pr = ^7C_2 \times (0.235)^2 \times (1 - 0.235)^{7 -2}}$

$\mathbf{Pr = 21 \times (0.235)^2 \times (0.765)^5}$

$\mathbf{Pr = 0.3039}$

Hence, the probability that he hits exactly 2 in the next 7 bats is 0.3039

Read more about probabilities at:

https://brainly.com/question/11234923