Answer:
[tex]x<=47/6[/tex] or [tex](-\infty, 47/6][/tex]
Step-by-step explanation:
Note that [tex]6.3333 = 6 1/3 = 19/3 = 38/6[/tex].
Also, note that [tex]1.5 = 1 1/2 = 3/2 = 9/6[/tex].
So, the inequality is really equal to [tex]x-38/6<=9/6[/tex].
We can then add [tex]38/6[/tex] to both sides to get [tex]x<=47/6[/tex].
So, the solution is [tex]x<=47/6[/tex], or in interval notation, [tex](-\infty, 47/6][/tex]
