Question

An oxygen gas sample has a volume of 31.0 L at 17.0 oC. What is the volume of this gas sample if it was heated to 34.0 o C?
Group of answer choices

2.95 L

62.0L

56.7 L

43.5 L

32.8 L

Answer 1

The volume of this gas sample if it was heated to 34.0°C is 32.8L

CHARLE'S LAW EQUATION:

• The relationship between the volume and temperature of a given gas can be represented using Charles law equation as follows:

V1/T1 = V2/T2

Where;

1. V1 = initial volume of gas (L)
2. V2 = final volume of gas (L)
3. T1 = initial temperature of gas (K)
4. T2 = final temperature of gas (K)

• According to this question;

V1 = 31L

V2 = ?

T1 = 17°C = 17 + 273 = 290K

T2 = 34°C = 34 + 273 = 307K

• V2 can be calculated as follows:

31/290 = V2/307

307 × 31 = 290V2

9517 = 290V2

V2 = 9517 ÷ 290

V2 = 32.81L

• Therefore, the volume of this gas sample if it was heated to 34.0°C is 32.8L

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