Question

Answer plss asap i beg

Answer 1

Answer: number 2

Step-by-step explanation: Give me a thank please

Answer 2

Answer:

3²

Step-by-step explanation:

You can rewrite the given problem as follows:

$3^{-6} * (\frac{3^{4} }{3^{0} })^{2}$

The first thing you must do is work on the terms inside the parenthesis.

According to the Zero exponent rule: $a^{0} = 1$. This means that any number or variable raised to the 0 power will equal 1. Therefore, the denominator inside the parenthesis is 1.

$3^{-6} * (\frac{3^{4} }{1})^{2}$

$= 3^{-6} * (3^{4})^{2}$

Next, according to the Power-to-Power Rule: $(a^{m})^{n} = a^{m*n}$

Therefore, you can multiply the exponent, 2, into $3^{4}$:

$= 3^{-6} * 3^{(4*2)}$

$= 3^{-6} * 3^{8}$

Then, the you can also apply the Negative Exponent Rule for rewriting $3^{-6}$:

$a^{-n} = \frac{1}{a^{n} }$

Therefore,  $3^{-6}$ will become: $3^{-6} = \frac{1}{3^{6} }$

$= \frac{1}{3^{6}} * 3^{8} = \frac{3^{8}}{3^{6}}$

Finally, the Quotient Rule states that:

$\frac{a^{m} }{a^{n} } = a^{(m-n)}$

Therefore:

$\frac{3^{8} }{3^{6} } = 3^{(8-6)} = 3^{2}$

The correct answer is 3²