A right circular cylinder has a height of 20 1/2 ft and a diameter 1 1/5 times its height.

What is the volume of the cylinder?

Enter your answer as a decimal in the box. Use 3.14 for pi and round only your final answer to the neares
hundredth.

Respuesta :

  • Height=h=20-1/2=20.5ft
  • Diameter=1-1/5=1.2
  • Radius=1.2/2=0.6ft

[tex]\\ \sf\longmapsto V=\pi r^2h[/tex]

[tex]\\ \sf\longmapsto V=3.14(0.6)^2(20.5)[/tex]

[tex]\\ \sf\longmapsto V=3.14(0.36)(20.5)[/tex]

[tex]\\ \sf\longmapsto V=23.17ft^3[/tex]

Answer:

[tex] \sf 9738 \frac{5373}{10.000} \: ft \approx 9738,5373 \: ft[/tex]

Step-by-step explanation:

Cylinder radius length

diameter = (20½ × 1 ⅕)

diameter = [tex] \sf \frac{41}{2} \times \frac{6}{5}[/tex]

diameter = [tex] \sf \frac{41 \times 6}{2 \times 5}[/tex]

diameter = [tex] \sf \frac{246}{10} \: ft[/tex]

r = [tex] \sf \frac{246}{10} \times \frac{1}{2}[/tex]

r = [tex] \sf \frac{246}{20}[/tex]

r = [tex] \sf \frac{123}{10} \: ft[/tex]

Cylinder Volume

Volume = π × r² × t

Volume = 3.14 × [tex] \sf (\frac{123}{10})²[/tex] × 20½

Volume = 3.14 × [tex] \sf \frac{15.129}{100} [/tex] × 20½

Volume = [tex] \sf \frac{2.375.253}{5000} [/tex] × 20½

Volume = [tex] \sf 9738 \frac{5373}{10.000} \: ft \approx 9738,5373 \: ft[/tex]

Conclusion:

Cylinder Volume is [tex] \sf 9738 \frac{5373}{10.000} \: ft \approx 9738,5373 \: ft[/tex].

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