Question

What are the zeros of the quadratic 3(x+4)(x-12)=0

Answer 1

Answer:

x=−4andx=12

Step-by-step explanation:

3(x + 4) * (x - 12) = 03(x+4)∗(x−12)=0

divide both sides

(x + 4)(x - 12) = 0(x+4)(x−12)=0