Question

Vector A⃗ has magnitude 5.1 m and points to the right; vector B⃗ has magnitude 4.0 m and points vertically upward. What is the magnitude of the vector C⃗ that satisfies A⃗ +B⃗ +C⃗ =0⃗

Answer 1

The magnitude of the vector C that satisfies the expression is 6.48m

Given the following magnitude;

Vector A = 5.1m

Vector B = 4.0m (upward)

Taking the resultant vector of A and B we will have:

$R=\sqrt{A^2+B^2}\\R=\sqrt{5.1^2+4.0^2}\\R= \sqrt{26.01+16}\\R=\sqrt{42.01}\\R= 6.48m$

Given the expression A⃗ +B⃗ +C⃗ =0⃗

R + C = 0

C = 0 - R

C = 0 - 6.48

C = -6.48m

Hence the magnitude of the vector C that satisfies the expression is 6.48m

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