What is the area of the trapezoid shown below?

Answer:
[tex]180units^{2}[/tex]
Step-by-step explanation:
[tex]Area = \frac{1}{2} *(a + b )*h\\\\[/tex]
Here,
(a+b) = sum of the parallel sides
h = perpendicular distance between parallel sides
Before find the area we have to find the perpendicular distance between parallel side by using Pythagorean theorem
[tex]7^{2} + h^{2}= 25^{2}\\49+h^{2} =625 \\h^{2}= 625-49\\h^{2}=576\\h = \sqrt{576} \\h=24[/tex]
Now let's find the area
[tex]Area = \frac{1}{2} *(a + b )*h\\\\[/tex]
[tex]=\frac{1}{2}*(11+4)*24\\=\frac{1}{2}*15*24\\ =180units^{2}[/tex]
Hope this helps you.
Let me know if you have any other questions :-)