The line is [tex]\rm y = \dfrac{x}{3} + 1[/tex].
Linear system
It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.
Given
A line m is passing through points (-1, 0) and (0, -3).
And the equation of the line that is perpendicular to line m and passes through the point (3,2).
To find
The equation of the line that is perpendicular to line m and passes through the point (3,2).
How to find the line?
A line m is passing through points (-1, 0) and (0, -3).
so the line will be y = -3x - 3, the slope m of the line is -3.
Let the slope of the perpendicular line be n and the line is y=nx+c.
The the product of slope of the perpendicular lines is -1.
mn = -1
-3n = -1
n = 1/ 3
Then the equation of the line will be y = x/3 + c
The line is passing through the point (3, 2), then
[tex]y = \dfrac{x}{3} +c\\\\2 = \dfrac{3}{3} + c\\\\2 = 1 +c\\\\c = 1[/tex]
Then the line is [tex]\rm y = \dfrac{x}{3} + 1[/tex].
More about the linear system link is given below.
https://brainly.com/question/20379472
