given:
length= 8 inch
width= 3 inch
to find:
the area and perimeter of the rectangle.
solution:
perimeter:
[tex]perimeter = l + l + w + w[/tex]
[tex]p = 8 + 8 + 3 + 3[/tex]
[tex]p = 22 \: inch[/tex]
area:
[tex]area = l \times w[/tex]
[tex]a = 8 \times 3[/tex]
[tex]a = 24 {in}^{2} [/tex]
