Please solve this problem.

Step-by-step explanation:
To find the value of x, we use a concept called as "The sum of interior angles on same side of transversal always measures 180° when added together".
Value of x :-
According to the concept,
[tex]\sf \leadsto (3x + 5) + (7x + 5) = {180}^{\circ}[/tex]
[tex]\sf \leadsto 3x + 7x + 5 + 5 = {180}^{\circ}[/tex]
[tex]\sf \leadsto 10x + 5 + 5 = {180}^{\circ}[/tex]
[tex]\sf \leadsto 10x + 10 = {180}^{\circ}[/tex]
[tex]\sf \leadsto 10x = 180 - 10[/tex]
[tex]\sf \leadsto 10x = 170[/tex]
[tex]\sf \leadsto x = \dfrac{170}{10}[/tex]
[tex]\sf \leadsto x = 17[/tex]
Now, let's find each of the angles.
Measurement of first angle :-
[tex]\sf \leadsto 3x + 5[/tex]
[tex]\sf \leadsto 3(17) + 5[/tex]
[tex]\sf \leadsto 51 + 5[/tex]
[tex]\sf \leadsto \angle{1} = {56}^{\circ}[/tex]
Measurement of second angle :-
[tex]\sf \leadsto 7x + 5[/tex]
[tex]\sf \leadsto 7(17) + 5[/tex]
[tex]\sf \leadsto 119 + 5[/tex]
[tex]\sf \leadsto \angle{2} = {124}^{\circ}[/tex]
Measurement of third angle :-
[tex]\sf \leadsto Straight \: line \: angle = {180}^{\circ}[/tex]
[tex]\sf \leadsto {56}^{\circ} + \angle{3} = {180}^{\circ}[/tex]
[tex]\sf \leadsto \angle{3} = 180 - 56[/tex]
[tex]\sf \leadsto \angle{3} = {124}^{\circ}[/tex]
Measurement of fourth angle :-
[tex]\sf \leadsto Straight \: line \: angle = {180}^{\circ}[/tex]
[tex]\sf \leadsto {124}^{\circ} + \angle{4} = {180}^{\circ}[/tex]
[tex]\sf \leadsto \angle{4} = 180 - 124[/tex]
[tex]\sf \leadsto \angle{4} = {56}^{\circ}[/tex]
Therefore, the ∠1, ∠2, ∠3 and ∠4 measures 56°, 124°, 56° and 124° respectively. The value of x is 17.