Question

the time period of an oscillating body is T how will the time of the period vibrating body change if the value of G is decreased by 9 times

Answer 1

$\\ \sf\longmapsto T_1=2\pi \sqrt{\dfrac{m}{g}}$

• g be x

$\\ \sf\longmapsto T_1=2\pi \sqrt{\dfrac{m}{x}}$

• G be 9x

$\\ \sf\longmapsto T_2=2\pi \sqrt{\dfrac{m}{G}}$

$\\ \sf\longmapsto T_2=2\pi \sqrt{\dfrac{m}{9x}}$

Now

$\\ \sf\longmapsto \dfrac{T_1}{T_2}=\dfrac{2\pi \sqrt{\dfrac{m}{x}}}{2\pi \sqrt{\dfrac{m}{9x}}}$

$\\ \sf\longmapsto \dfrac{T_1}{T_2}=\dfrac{1}{9}$

$\\ \sf\longmapsto T_1:T_2=1:9$

The time period will increase by 9 times