Determine the value of f(2) for the function f(x) = x^3+18x^2+99x+162 for x < -3...

The value of f(2) for the function f(x) is f(2) = 0.
Since f(x) = x³ + 18x² + 99x + 162 for x < -3
f(x) = (3x - 6)/(x² - 7x + 6) for -3 < x ≤ 2
f(x) = √(x² - 4) for x > 2
Since we require f(2) and the expression in the middle covers the range -3 < x ≤ 2, so we use this expression.
f(x) = (3x - 6)/(x² - 7x + 6)
So, f(2) = (3(2) - 6)/((2)² - 7(2) + 6)
f(2) = (6 - 6)/(4 - 14 + 6)
f(2) = 0/-4
f(2) = 0
So, the value of f(2) for the function f(x) is f(2) = 0.
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