Question

Complete the following.
(a) The graph of y=h(x) is shown. Draw the graph of y = h (2x) +1.

Answer 1

The attached graph represents the graph of the function y = h(2x) + 1

How to draw the graph?

The points on the graph of y= h(x) are:

(-1,-2), (-2,-4), (0,0), (2,-1), (4,-2)

Using the above ordered pairs, the points on y = h(2x) + 1 are:

When x = -1, h(2x) = h(-2) = -4

So, we have:

y = -4 + 1 = -3

When x = -2, h(2x) = h(-4) = -8

So, we have:

y = -8 + 1 = -7

When x = 0, h(2x) = h(0) = 0

So, we have:

y = 0 + 1 = 1

When x = 2, h(2x) = h(4) = -2

So, we have:

y = -2 + 1 = -1

When x = 4, h(2x) = h(8) = -4

So, we have:

y = -4 + 1 = -3

So, the points on the graph of y = h(2x) + 1 are:

(-2,-7), (-1,-3),  (0,1), (2,-1), (4,-3)

Next, we plot the graph of y = h(2x) + 1

See attachment for the graph of y = h(2x) + 1

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https://brainly.com/question/1548871

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