If 4=118 degrees, what is the measure of each of the other angles?

Given that angle 4 is 118 degrees, by applying our knowledge of the special angles formed when a transversal intersects two parallel lines, the measure of the other angles can be calculated as:

m<1 = 62 degrees
m<2 = 118 degrees
m<3 = 62 degrees
m<5 = 62 degrees
m<6 = 118 degrees
m<7 = 62 degrees
m<8 = 118 degrees

Given:

m<4 = 118 degrees

Applying our knowledge of the special angles formed when a transversal intersects 2 parallel lines, we can find the rest of the angles as follows:

Find m<1:

<1 and <4 are a linear pair

Therefore:

m<1 = 180 - 118 = 62 degrees (angles of a linear pair are supplementary).

Find m<2 :

<2 and <4 are vertical angles

Therefore:

m<2 = m<4 = 118 degrees (vertical angles are congruent).

Find m<3:

<3 and <1 are vertical angles

Therefore:

m<3 = m<1 = 62 degrees (vertical angles are congruent).

Find m<5:

<5 and <1 are corresponding angles

Therefore:

m<5 = m<1 = 62 degrees (corresponding angles are congruent).

Find m<6 :

<6 and <2 are corresponding angles

Therefore:

m<6 = m<2 = 118 degrees (corresponding angles are congruent).

Find m<7:

<7 and <5 are vertical angles

Therefore:

m<7 = m<5 = 62 degrees (vertical angles are congruent).

Find m<8:

<8 and <6 are vertical angles

Therefore:

m<8 = m<6 = 118 degrees (vertical angles are congruent).

In summary, given that angle 4 is 118 degrees, by applying our knowledge of the special angles formed when a transversal intersects two parallel lines, the measure of the other angles can be calculated as:

m<1 = 62 degrees
m<2 = 118 degrees
m<3 = 62 degrees
m<5 = 62 degrees
m<6 = 118 degrees
m<7 = 62 degrees
m<8 = 118 degrees

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