Respuesta :

Answer:

• The first equation:

[tex]{ \rm{3y = x - 25}} \\ \\ { \boxed{ \rm{x - 3y = 25}}}[/tex]

• The second equation:

[tex]{ \rm{3y + (x - 25) = 118}} \\ \\ { \boxed{ \rm{3y + x = 143}}}[/tex]

• Adding the first equation and second equation:

[tex]{ \underline{ \rm{ + \binom{x - 3y = 25}{x + 3y = 143} }}} \\ { \rm{2x + 0y = 168}} \\ \\ { \tt{2x = 168}} \\ \\ { \boxed{ \boxed{ \tt{ \: \: x = 84 \: \: }}}}[/tex]

• find y from first equation:

[tex]{ \rm{x - 3y = 25}} \\ \\ { \tt{84 - 3y = 25}} \\ \\ { \tt{3y = 59}} \\ \\ { \boxed{ \boxed{ \tt{ \: \: y = 19.67 \approx \: 20}}}}[/tex]

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