Question

A frequency distribution is shown below. Complete parts (a) and (b).
The number of televisions per household in a small town
Televisions 0
1
2
3
Households 30
440 726 1403
(a) Use the frequency distribution to construct a probability distribution.
P(x)
0
х
CU NR
3
(Round to three decimal places as needed.)

Answer 1

Using the concept of probability, the distribution is:

$P(X = 0) = 0.012$

$P(X = 1) = 0.169$

$P(X = 2) = 0.279$

$P(X = 3) = 0.54$

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• A probability is the number of desired outcomes divided by the number of total outcomes.

• In total, there are 30 + 440 + 726 + 1403 = 2599 households.

Of those, 30 have 0 televisions, thus:

$P(X = 0) = \frac{30}{2599} = 0.012$

440 have 1, then:

$P(X = 1) = \frac{440}{2599} = 0.169$

726 have 2 and 1403 have 3, then:

$P(X = 2) = \frac{726}{2599} = 0.279$

$P(X = 3) = \frac{1403}{2599} = 0.54$

The distribution gives the probability of each outcome, thus:

$P(X = 0) = 0.012$

$P(X = 1) = 0.169$

$P(X = 2) = 0.279$

$P(X = 3) = 0.54$

A similar problem is given at https://brainly.com/question/24141790