The mass of Na that contains 4.653×10¹⁹ atoms is 0.0018 g
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole
Thus,
6.02×10²³ atoms = 1 mole of Na
Recall:
1 mole of Na = 23 g
Thus, we can say that:
6.02×10²³ atoms = 23 g of Na
With the above information in mind, we can determine the mass of Na that contains 4.653×10¹⁹ atoms. This can be obtained as follow:
6.02×10²³ atoms = 23 g of Na
Therefore,
4.653×10¹⁹ atoms = [tex]\frac{4.653*10^{19} * 23}{6.02*10^{23} }[/tex]
4.653×10¹⁹ atoms = 0.0018 g of Na
Therefore, 0.0018 g of Na contains 4.653×10¹⁹ atoms.
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