Question

If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?

Answer 1

The definition of eccentricity allows us to find that the answer for the distance to the focus is

             c = 4.6 10⁶ km

The orbit of the plants without ellipses, where the eccentricity is the ratio between the distance to the focus and the major axis  

                e = $\frac{c}{a}$

Where e is the eccentricity, c the distance to the focus and a the major axis

In this case they indicate the value of the eccentricity e = 0.92 and the value of the major axis a = 5 10⁶ km

              c = e a

Let's calculate

              c = 0.92 5 10⁶

              c = 4.6 10⁶ km

In conclusion using the definition of eccentricity we can calculate the distance to the focus is

             c = 4.6 10⁶ km

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