Respuesta :

Answer:

[tex](\sqrt{3}-i)^{6},(\sqrt{3}-\sqrt{3}i)^{4},(\sqrt{2}-i)^{6}, (\sqrt{2}-\sqrt{2}i)^{8},(-1+\sqrt{3}i)^{12}[/tex]

Step-by-step explanation:

[tex](\sqrt{3}-\sqrt{3}i)^{4}=-36\\(\sqrt{2}-\sqrt{2}i)^{8}=256\\(-1+\sqrt{3}i)^{12}=4096\\(\sqrt{2}-i)^{6}=-23+10\sqrt{2}i\\(\sqrt{3}-i)^{6}=-64[/tex]

[tex](\sqrt{3}-i)^{6},(\sqrt{3}-\sqrt{3}i)^{4},(\sqrt{2}-i)^{6}, (\sqrt{2}-\sqrt{2}i)^{8},(-1+\sqrt{3}i)^{12}[/tex]

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