Respuesta :

Integers are positive and negative numbers without decimal points.

  • The integer solutions are: x = 1, y = 2
  • There is no integer solution to [tex]\mathbf{4x + 10y = 9}[/tex]
  • The integer solutions are: x = -3, y = 2
  • The integer solutions are: x = 9, y = 4

[tex]\mathbf{(a)\ 3x + 2y = 1}[/tex]

Set x = 1

So, we have:

[tex]\mathbf{3\times -1 + 2y = 1}[/tex]

[tex]\mathbf{-3 + 2y = 1}[/tex]

Collect like terms

[tex]\mathbf{2y = 1+3}[/tex]

[tex]\mathbf{2y = 4}[/tex]

Divide both sides by 2

[tex]\mathbf{y = 2}[/tex]

Hence, the integer solutions are: x = 1, y = 2

[tex]\mathbf{(b)\ 4x + 10y = 9}[/tex]

  • The coefficient of x and y are even numbers.
  • This means that: 4x and 10y are even numbers
  • 9 is an odd number

The sum of even numbers cannot give an odd number.

Hence, there is no integer solution to [tex]\mathbf{4x + 10y = 9}[/tex]

[tex]\mathbf{(c)\ 7x + 23y = 25}[/tex]

Set y = 2

So, we have:

[tex]\mathbf{7x + 23 \times 2 = 25}[/tex]

[tex]\mathbf{7x + 46 = 25}[/tex]

Collect like terms

[tex]\mathbf{7x = 25 - 46}[/tex]

[tex]\mathbf{7x = -21}[/tex]

Divide both sides by 7

[tex]\mathbf{x = -3}[/tex]

Hence, the integer solutions are: x = -3, y = 2

[tex]\mathbf{(d)\ x^2 - 4y^2 = 17}[/tex]

Set x = 9

So, we have:

[tex]\mathbf{9^2 - 4y^2 = 17}[/tex]

[tex]\mathbf{81 - 4y^2 = 17}[/tex]

Collect like terms

[tex]\mathbf{- 4y^2 = 17 - 81}[/tex]

[tex]\mathbf{- 4y^2 = -64}[/tex]

Divide both sides by -4

[tex]\mathbf{y^2 = 16}[/tex]

Take square roots of both sides

[tex]\mathbf{y = 4}[/tex]

Hence, the integer solutions are: x = 9, y = 4

Read more about integer solutions at:

https://brainly.com/question/4928961

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