All circles are similar but all circles are not congruent.
The true statement is that: b) the image and pre-image points are on the same circle
From the complete question, we understand that:
The above statements means that:
Point D is equidistant from point B and point C
In other words
[tex]\mathbf{DB = DC}[/tex]
This can further be rewritten as:
[tex]\mathbf{radius = DB = DC}[/tex]
The above statement means that:
The radii of both circles are equal
When two circles have the same radius, then the circles are similar and congruent
Hence, the true statement is option (b):
See attachment for the illustration of circle constructions
Read more about circles at:
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