Respuesta :

9514 1404 393

Answer:

  B

Step-by-step explanation:

The inverse function is the solution to ...

  x = f(y)

  x = 3√y -2 . . . . use given f(x)

  x +2 = 3√y . . . . add 2

  (x +2)/3 = √y . . . . divide by 3

  ((x +2)/3)^2 = y . . . . square both sides

Then the inverse function is ...

  [tex]f^{-1}(x)=(\dfrac{x+2}{3})^2\qquad\text{matches choice B}[/tex]

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Additional comment

The range of the original quadratic is f(x) ≥ -2. This will be the domain of the inverse function: x ≥ -2.

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