Question

QUESTION:

Y is between X and Z. If XY=5x+1, YZ=2x+5, and XZ=27, what is the value of XY? pls show work!!!!!!

Answer 1

Answer:

XY = 16

Step-by-step explanation:

XY  + YZ = XZ so:

5x + 1 + 2x + 5 = 27

5x + 2x + 5 + 1 = 27

7x + 6 = 27

Subtract 6 from both sides:

7x + 6 - 6 = 27  - 6

7x = 21

Divide both sides by 7:

7x ÷ 7 = 21 ÷ 7

x = 3

XY = 5x + 1 so substitute in known x:

5(3) + 1 =

15 + 1 = 16

So XY = 16

Hope this helps!

Answer 2

Answer:

$XY = 16$

Step-by-step explanation:

Given,

$XY = 5x + 1$

$YZ = 2x + 5$

$XZ = 27$

Also,

$XZ =XY + YZ$

$XZ = (5x + 1) + (2x + 5)$

$27 = (5x + 2x) + (1 + 5)$

$27 = 7x + 6$

$27 - 6 = 7x$

$21 = 7x$

$\frac{21}{7} = x$

$3 = x$

Now,

We know that,

$XY = 5x + 1$

$XY = 5(3) + 1$

$XY = 15 + 1$

$XY = 16$