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Answer:
f^-1(x) = √(6/(9 -x))
Step-by-step explanation:
The inverse function is the solution to ...
x = f(y)
x = 9 -6/y^2
x +6/y^2 = 9 . . . . . add 6/y^2
6/y^2 = 9 -x . . . . . subtract x
6/(9 -x) = y^2 . . . . . multiply by y^2/(9 -x)
y = √(6/(9 -x)) . . . . take the square root
Then the inverse function can be written as ...
f^-1(x) = √(6/(9 -x)) . . . . . . x < 9
