Question

The world record for diving without supplemental air tanks (breath-hold diving) is about 125 m, a depth at which the pressure is about 12.5 atm. If a diver’s lungs contain 6.0 liters of air at the surface of the water, what is this volume at a depth of 125 m?

Answer 1

At a depth of 125m, the volume of air in the diver's lungs decreases to 0.48L.

Given the data in the question;

• V₁ = 6.0L
• V₂ = ?

We know that, at the surface of the water, standard atmospheric pressure is 1, thus;

• P₁ = 1atm
• P₂ = 12.5atm

Now, to determine the volume V₂, we use Boyle's Law; which say:

$P_1 * V_1 = P_2 * V_2$

We make $V_2$ the subject of the formula

$V_2 = \frac{P_1*V_1}{P_2}$

Next, we substitute in our given values

$V_2 = \frac{1atm\ *\ 6.0L}{12.5atm}$

$V_2 = 0.48L$

Therefore, at a depth of 125m, the volume of air in the diver's lungs decreases to 0.48L.

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