Question

5 molNa and 5 molBr2 Express your answer as a chemical formula.

Find the limiting reactant for each initial amount of reactants in the following reaction:

2Na(s)+Br2(g)→2NaBr(s)

Answer 1

The limiting reactant is sodium.

From the reaction equation;

2Na(s)+Br2(g)→2NaBr(s)

We know that the limiting reactant yields the least number of moles of product;

For sodium;

2 mole of Na yields 2 moles of NaBr from the equation

5 moles of Na yields  5 moles of NaBr

For bromine;

1 mole of Br2 yields 2 moles of NaBr

5 moles of Na Br yields 5 × 2/1 = 10 moles of NaBr

We can see that sodium is the limiting reactant here.

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