The addition of vectors allows finding that the arrival airport is 1506.02 km and 15.02º North of the East, from Dalas airport.
Displacement is a vector quantity that must be calculated with vector algebra. Its magnitude can be calculated with the Pythagorean Theorem and using trigonometry its direction can be found
Let's calculate the magnitude of the vector from the departure airport (Dalas) to the arrival airport, in the attached we can see a diagram of this displacement
d² = x² + y²
d = [tex]\sqrt{1454.55^2 + 390.27^2}[/tex]
d = 1506.02 km
The direction of this airport can be calculated using trigonometry
tan θ = y / x
θ = tan -1 y / x
θ = tan-1 390.27 / 1454.55
θ = 15.02º
angle can be written 15.02º North of East
In conclusion with the addition of vectors we can find that the arrival airport is 1506.02 km and 15.02º North of the East of Dalas airport.
Learn more about adding vectors here:
https://brainly.com/question/24643991
