Question

If 26.5 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed in the following precipitation reaction?
2 NaOH(aq) + Mn(NO₃)₂(aq) → Mn(OH)₂ (s) + 2 NaNO₃(aq)

Answer 1

I outlined the numbers 1 and 2 to show the sequence of the solution.

Hope you can understand. All the best!