1. For the Function f(x)= -4 sqrt x-1, find the inverse function.

2. The function f(x)=(x-1)^2-4 is not-one-to-one. If you restrict the domain f(x) to x (less or equal) 1, what is it’s inverse function and the domain for the inverse?

The domain of the inverse function is the range of the function. Function values for x ≥ 0 will be -1 or less, Hence the domain of the inverse function will be x ≤ -1.

In order to match the function's domain of x ≥ 0, the range of the inverse function must be non-negative values. Hence there can be no minus sign in front of the squared expression. The inverse function must be ...

[tex]f^{-1}(x)=\dfrac{(x+1)^2}{16},x\le-1[/tex]

1. For the Function f(x)= -4 sqrt x-1, find the inverse function. 2. The function f(x)=(x-1)^2-4 is not-one-to-one. If you restrict the domain f(x) to x (less or equal) 1, what is it’s inverse function and the domain for the inverse?

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1. For the Function f(x)= -4 sqrt x-1, find the inverse function.

2. The function f(x)=(x-1)^2-4 is not-one-to-one. If you restrict the domain f(x) to x (less or equal) 1, what is it’s inverse function and the domain for the inverse?