Respuesta :
The question is an illustration of similar triangles.
The distance across the river is 500ft
From the question (see attachment), we have:
[tex]\mathbf{RO = 170}[/tex]
[tex]\mathbf{RE = 250}[/tex]
[tex]\mathbf{OC = 335}[/tex]
Because, triangles PRE and POC are similar, we can make use of the following equivalent ratios
[tex]\mathbf{PR:RE = PO:OC}[/tex]
Where:
[tex]\mathbf{ PO = PR + RO}[/tex]
Express [tex]\mathbf{PR:RE = PO:OC}[/tex] as a fraction
[tex]\mathbf{\frac{PR}{RE} = \frac{PO}{OC}}[/tex]
Substitute[tex]\mathbf{ PO = PR + RO}[/tex]
[tex]\mathbf{\frac{PR}{RE} = \frac{PR + RO}{OC}}[/tex]
Substitute known values
[tex]\mathbf{\frac{PR}{250} = \frac{PR + 170}{335}}[/tex]
Cross multiply
[tex]\mathbf{335 \times PR = 250 \times (PR + 170)}[/tex]
Open brackets
[tex]\mathbf{335 \times PR = 250 \times PR + 250 \times 170}[/tex]
Collect like terms
[tex]\mathbf{335 \times PR - 250 \times PR = 250 \times 170}[/tex]
Factor out PR
[tex]\mathbf{(335 - 250) \times PR = 250 \times 170}[/tex]
Make PR the subject
[tex]\mathbf{PR = \frac{250 \times 170}{(335 - 250)}}[/tex]
[tex]\mathbf{PR = \frac{42500}{85}}[/tex]
[tex]\mathbf{PR = 500}[/tex]
Hence, the distance across the river is 500ft
Read more about similar triangles at:
https://brainly.com/question/20502441
