Question

8. When a force is applied to an object, the object's acceleration (varies inversly with the square
of it's mass. When the force is applied on a mass of 5kg, the acceleration is 4m/s2 If a
similar force is applied to another object, its acceleration is 0.1m/s2. What is the mass of the
object? Round your answer to the hundreths place.

Answer 1

When a force is applied to an object, the mass of the  object rounded to the hundredths place is 0.79 kilograms.

• Let the first object be A.

• Let the second object be B.

Given the following data:

• Mass A = 5 kg

• Acceleration A = 4 $m/s^2$

• Acceleration A = 0.1 $m/s^2$

To find the mass of object B:

First of all, we would solve for the force acting on the two objects.

Translating the statement into an inverse expression, we have;

$F = \frac{a}{m^2}$

Substituting the values into the equation, we have:

$F = \frac{4}{5^2}\\\\F = \frac{4}{25}\; Newton$

Next, we would determine the mass of object B;

$\frac{4}{25} = \frac{0.1}{B^2}$

Cross-multiplying, we have:

$4B^2 = 25$ × $0.1$

$4B^2 = 2.5\\\\B^2 = \frac{2.5}{4} \\\\B^2 = 0.625\\\\B = \sqrt{0.625}$

Mass B = 0.79 kg

Therefore, the mass of the  object rounded to the hundredths place is 0.79 kg.

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