Question

Part F
For both Tracker experiments, calculate the average vertical acceleration, where the time period is t = 0.10 second tot = 1.00 second. Consider
only the magnitude of the vertical velocity in the calculations. Record your results to three significant figures.
Comment: How does the average acceleration of the two balls compare to the theoretical value of -9.81 meters/second, and how do the
accelerations of the two balls compare to each other?

Answer 1

At an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.

Generally, acceleration is defined as the change in velocity per change in time of motion.

Acceleration of an object at any given time, t, can be calculated using the following equations below;

$a = \frac{\Delta v}{\Delta t} = \frac{v-u}{t_2-t_1}$

where;

• v is final velocity at t₂
• u is the initial velocity at t₁
• t₂ is the final time of motion
• t₁ is the initial time of motion

From the formula above, we can conclude that at an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.

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Answer 2

Answer:

t an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.

Generally, acceleration is defined as the change in velocity per change in time of motion.

Acceleration of an object at any given time, t, can be calculated using the following equations below;

Explanation: