Question

A 40 kg boy running at 3.0 m/s jumps onto a 2.0 kg skateboard calculate the final velocity of the boy and the skateboard

Answer 1

The final velocity of the boy and the skateboard is 2.86 m/s

The given parameters;

mass of the boy, m = 40 kg

initial velocity of the boy, u = 3 m/s

mass of the skateboard, m₂ = 2 kg

The final velocity of the boy and the skateboard is calculated by applying the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

40 x 3 + 0 = v(40 + 2)

120 = 42v

$v = \frac{120}{42} \\\\v = 2.86 \ m/s$

Thus, the final velocity of the boy and the skateboard is 2.86 m/s

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