Question

SOMEBODY PLS HELP ME <3

Answer 1

$\boxed{\sf Slope=m=tan\Theta=\dfrac{y_2-y_1}{x_2-x_1}}$

Looking at options

#A

$\\ \sf\longmapsto m=\dfrac{3}{-3}=-1$

• Negative slope

#B

$\\ \sf\longmapsto m=tan\Theta=tan0=0$

• omitted

#C

• Line parallel to y axis hence any points have same x co-ordinate for which the x_2-x_1=0

$\\ \sf\longmapsto m=tan90=\infty$

• omitted

#D

$\\ \sf\longmapsto m=\dfrac{3}{3}=1$

• Positive slope

Hence option D is correct

Answer 2

Answer:

• The first graph.

→ Consinder points (-2, 0) and (-3, -1) from the graph:

${ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }} \\ \\ { \tt{slope = \frac{0 - ( - 1)}{ - 2 - ( - 3)} = \frac{1}{1} }} \\ \\ { \boxed{ \tt{slope = {}^{ + } 1}}}$