Question

1) A race car travels east with a forward velocity of 40 m/s and slows at a constant rate
to 16 m/s over 9 S.

Answer 1

• initial velocity=u=40m/s
• Time=t=9s
• Acceleration=+16m/s^2

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=40+(16)(9)$

$\\ \sf\longmapsto v=40+144$

$\\ \sf\longmapsto v=184m/s$

Answer 2

Explanation:

• v=u+at
• v=40+16×9
• v=40+144
• v=184 m/s