The busses will arrive again at the same time in 135 minutes.
The given parameters;
at stop A = bus arrives every 14 minutes
at stop B = bus arrives every 20
The lowest common multiple of 14 and 20 is calculated as;
14 = 2 x 7
20 = 2² x 5
LCM = 2² x 5 x 7 = 4 x 5 x 7 = 140
The common time for both busses = 140 minutes
Before this 140 minutes, the busses have spent 5 minutes moving
The buses will arrive at the same stop again in:
140 minutes - 5 minutes = 135 minutes
Thus, the busses will arrive again at the same time in 135 minutes.
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