Question

The amount of time in seconds, t, it takes for a bungee jumper to free fall is given by the function t equals the square root of the quantity d over 16 end quantity comma where d represents the distance that the object falls, in feet. If a bungee jumper free falls for 4 seconds, how far does the jumper fall?

4,096 feet
256 feet
128 feet
64 feet

Answer 1

The height of fall of the bungee jumper is 4,096 feet.

The given function;

$f(t) = \frac{\sqrt{d} }{16}$

where;

t is the time of the motion, s

d is the distance the object falls, feet

When, the time of motion is 4 seconds, the distance the bungee jumper falls is calculated as follows;

$4 = \frac{\sqrt{d} }{16}$

multiply both sides of the equation by 16;

√d = 16(4)

√d = 64

square both sides of the equation;

d = (64)²

d = 4,096 feet

Thus, the height of fall of the bungee jumper is 4,096 feet.

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Answer 2

Answer:

256 seconds

Step-by-step explanation:

t=√d/16

4 seconds=√d/16

d=16x4^2

d=16x16

d=256