Let g be a horizontal shrink by a factor of 2/3, followed by a translation 4 units left of the graph of f(x)= √6x. Write a rule for g described by the transformations of the graph of f.

Respuesta :

If g is a horizontal shrink by a factor of 2/3, followed by a translation 4 units left of the graph of f(x)= √6x, the sequence of transformation from f(x) to g(x) is:

Dilation by a factor of 2/3

Horizontal translation to the left by 4 units

g(x) = 2/3 [√6(x - 4)]

The given function is f(x)= √6x

Shrink the function f(x)= √6x by a factor of 2/3, the resulting function becomes 2/3 (√6x)

Translate the resulting function by 4 units to the left of the graph to form g(x)

g(x) = 2/3 [√6(x - 4)]

Therefore, the sequence of transformation from f(x) to g(x) is:

Dilation by a factor of 2/3

Horizontal translation to the left by 4 units

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