Someone please help!!

From the given right angle triangle ,
the value of x is 60.6°
Given :
A diagram of a triangle with side length RQ is 27 and QS is 55
We need to find out angle x
Given triangle is a right angle triangle . So we use trigonometric ratios to find out the angle x
For angle x, we are given with hypotenuse QS=55 and adjacent side RQ= 27
We use trigonometric ratio cos
[tex]cos(Q)= \frac{adjacent}{hypotenuse } \\cos(x)=\frac{27}{55}\\\\x=\arccos \left(\frac{27}{55}\right)[/tex]
Now use the calculator and find out x
x=60.6°
Learn more : brainly.com/question/17198769