A polynomial function of least degree with integral coefficients that has the
given zeros [tex]f(x)=x^4+x^3+9x^2+9x[/tex]
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros
[tex]\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)[/tex]
Now we multiply it to get the polynomial
[tex]x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x[/tex]
polynomial function of least degree with integral coefficients that has the
given zeros [tex]f(x)=x^4+x^3+9x^2+9x[/tex]
Learn more : brainly.com/question/7619478