Question

For the generic reaction below, express the reaction rate as an equation in terms of rate of change of A, B, C, and D.

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Answer 1

For the generic reaction 2 A + 1.5 B ⇄ C + 4 D, the reaction rate in terms of rate of change of A, B, C, and D is $r = \frac{-\Delta [A] }{2 \Delta t} = \frac{-\Delta [B] }{1.5 \Delta t} = \frac{\Delta [C] }{ \Delta t} = \frac{\Delta [D] }{4 \Delta t}$.

Let's consider the following generic reaction.

2 A + 1.5 B ⇄ C + 4 D

The reaction rate is the speed at which a chemical reaction takes place. It is equal to the change in the molar concentrations over the change in time. However, since the reaction rate is unique for the reaction and the rate of each substance is affected by its stoichiometric coefficient, we have to divide the change in the concentration of a substance by its stoichiometric coefficient to discard that effect. Furthermore, since the reaction rate is by definition positive, and the concentration of the reactants decreases over time, we need to add a negative sign to discard that effect.

The reaction rate (r), in terms of the rate of change of A, B, C and D is:

$r = \frac{-\Delta [A] }{2 \Delta t} = \frac{-\Delta [B] }{1.5 \Delta t} = \frac{\Delta [C] }{ \Delta t} = \frac{\Delta [D] }{4 \Delta t}$

For the generic reaction 2 A + 1.5 B ⇄ C + 4 D, the reaction rate in terms of rate of change of A, B, C, and D is $r = \frac{-\Delta [A] }{2 \Delta t} = \frac{-\Delta [B] }{1.5 \Delta t} = \frac{\Delta [C] }{ \Delta t} = \frac{\Delta [D] }{4 \Delta t}$.

You can learn more about reaction rate here: https://brainly.com/question/3334857