Question

Find the quadratic function that has a vertex at (−2,−4) and goes through the point (−1,−5).


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Answer 1

Answer:

y=-x^2-4x-8 or  y=-(x+2)^2-4

Step-by-step explanation:

First use the vertex form(because you have vertex point)

y=a(x+2)^2-4

Then, plug in the point(-1,-5) to find the equation

-5=a(-1+2)^2-4

-5=a-4

a=-1

y=-(x+2)^2-4 = -x^2-4x-4-4 = -x^2-4x-8